2114(z+3)=14z+2

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Solution for 2114(z+3)=14z+2 equation: 



2114(z+3)=14z+2

We move all terms to the left:

2114(z+3)-(14z+2)=0

We multiply parentheses

2114z-(14z+2)+6342=0

We get rid of parentheses

2114z-14z-2+6342=0

We add all the numbers together, and all the variables

2100z+6340=0

We move all terms containing z to the left, all other terms to the right

2100z=-6340

z=-6340/2100

z=-3+2/105

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