21=(2x+10)+(x-4)

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Solution for 21=(2x+10)+(x-4) equation: 



21=(2x+10)+(x-4)

We move all terms to the left:

21-((2x+10)+(x-4))=0



We calculate terms in parentheses: -((2x+10)+(x-4)), so:

(2x+10)+(x-4)

We get rid of parentheses

2x+x+10-4

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

-3x-6+21=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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