21=(x+4)+x

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Solution for 21=(x+4)+x equation: 



21=(x+4)+x

We move all terms to the left:

21-((x+4)+x)=0



We calculate terms in parentheses: -((x+4)+x), so:

(x+4)+x

We add all the numbers together, and all the variables

x+(x+4)

We get rid of parentheses

x+x+4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

-2x-4+21=0

We add all the numbers together, and all the variables

-2x+17=0

We move all terms containing x to the left, all other terms to the right

-2x=-17

x=-17/-2

x=8+1/2

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