21=(x/4-3)=45

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Solution for 21=(x/4-3)=45 equation: 



21=(x/4-3)=45

We move all terms to the left:

21-((x/4-3))=0

We multiply all the terms by the denominator


-((x+21*4-3))=0



We calculate terms in parentheses: -((x+21*4-3)), so:

(x+21*4-3)

We add all the numbers together, and all the variables

(x+81)

We get rid of parentheses

x+81

Back to the equation:

-(x+81)



We get rid of parentheses

-x-81=0

We add all the numbers together, and all the variables

-1x-81=0

We move all terms containing x to the left, all other terms to the right

-x=81

x=81/-1

x=-81

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