21=-6y+3(y-2)

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Solution for 21=-6y+3(y-2) equation: 



21=-6y+3(y-2)

We move all terms to the left:

21-(-6y+3(y-2))=0



We calculate terms in parentheses: -(-6y+3(y-2)), so:

-6y+3(y-2)

We multiply parentheses

-6y+3y-6

We add all the numbers together, and all the variables

-3y-6

Back to the equation:

-(-3y-6)



We get rid of parentheses

3y+6+21=0

We add all the numbers together, and all the variables

3y+27=0

We move all terms containing y to the left, all other terms to the right

3y=-27

y=-27/3

y=-9

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