21=1/2b(2b+8)

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Solution for 21=1/2b(2b+8) equation: 



21=1/2b(2b+8)

We move all terms to the left:

21-(1/2b(2b+8))=0



Domain of the equation: 2b(2b+8))!=0

b∈R



We multiply all the terms by the denominator


-(1+21*2b(2b+8))=0



We calculate terms in parentheses: -(1+21*2b(2b+8)), so:

1+21*2b(2b+8)

determiningTheFunctionDomain
21*2b(2b+8)+1

Wy multiply elements

42b(2+1

Back to the equation:

-(42b(2+1)



We add all the numbers together, and all the variables

-(42b3=0

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