21=2(2m-4)+15

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Solution for 21=2(2m-4)+15 equation: 



21=2(2m-4)+15

We move all terms to the left:

21-(2(2m-4)+15)=0



We calculate terms in parentheses: -(2(2m-4)+15), so:

2(2m-4)+15

We multiply parentheses

4m-8+15

We add all the numbers together, and all the variables

4m+7

Back to the equation:

-(4m+7)



We get rid of parentheses

-4m-7+21=0

We add all the numbers together, and all the variables

-4m+14=0

We move all terms containing m to the left, all other terms to the right

-4m=-14

m=-14/-4

m=3+1/2

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