21=4(w-3)+5w

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Solution for 21=4(w-3)+5w equation: 



21=4(w-3)+5w

We move all terms to the left:

21-(4(w-3)+5w)=0



We calculate terms in parentheses: -(4(w-3)+5w), so:

4(w-3)+5w

We add all the numbers together, and all the variables

5w+4(w-3)

We multiply parentheses

5w+4w-12

We add all the numbers together, and all the variables

9w-12

Back to the equation:

-(9w-12)



We get rid of parentheses

-9w+12+21=0

We add all the numbers together, and all the variables

-9w+33=0

We move all terms containing w to the left, all other terms to the right

-9w=-33

w=-33/-9

w=3+2/3

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