21=5(u+3)-7u

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Solution for 21=5(u+3)-7u equation: 



21=5(u+3)-7u

We move all terms to the left:

21-(5(u+3)-7u)=0



We calculate terms in parentheses: -(5(u+3)-7u), so:

5(u+3)-7u

We add all the numbers together, and all the variables

-7u+5(u+3)

We multiply parentheses

-7u+5u+15

We add all the numbers together, and all the variables

-2u+15

Back to the equation:

-(-2u+15)



We get rid of parentheses

2u-15+21=0

We add all the numbers together, and all the variables

2u+6=0

We move all terms containing u to the left, all other terms to the right

2u=-6

u=-6/2

u=-3

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