21=5(u-3)+4u

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Solution for 21=5(u-3)+4u equation: 



21=5(u-3)+4u

We move all terms to the left:

21-(5(u-3)+4u)=0



We calculate terms in parentheses: -(5(u-3)+4u), so:

5(u-3)+4u

We add all the numbers together, and all the variables

4u+5(u-3)

We multiply parentheses

4u+5u-15

We add all the numbers together, and all the variables

9u-15

Back to the equation:

-(9u-15)



We get rid of parentheses

-9u+15+21=0

We add all the numbers together, and all the variables

-9u+36=0

We move all terms containing u to the left, all other terms to the right

-9u=-36

u=-36/-9

u=+4

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