21=7+3(c-2)

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Solution for 21=7+3(c-2) equation: 



21=7+3(c-2)

We move all terms to the left:

21-(7+3(c-2))=0



We calculate terms in parentheses: -(7+3(c-2)), so:

7+3(c-2)

determiningTheFunctionDomain
3(c-2)+7

We multiply parentheses

3c-6+7

We add all the numbers together, and all the variables

3c+1

Back to the equation:

-(3c+1)



We get rid of parentheses

-3c-1+21=0

We add all the numbers together, and all the variables

-3c+20=0

We move all terms containing c to the left, all other terms to the right

-3c=-20

c=-20/-3

c=6+2/3

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