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21=7x^2
We move all terms to the left:
21-(7x^2)=0
a = -7; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-7)·21
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*-7}=\frac{0-14\sqrt{3}}{-14} =-\frac{14\sqrt{3}}{-14} =-\frac{\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*-7}=\frac{0+14\sqrt{3}}{-14} =\frac{14\sqrt{3}}{-14} =\frac{\sqrt{3}}{-1} $
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