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21a^2+42a=-21
We move all terms to the left:
21a^2+42a-(-21)=0
We add all the numbers together, and all the variables
21a^2+42a+21=0
a = 21; b = 42; c = +21;
Δ = b2-4ac
Δ = 422-4·21·21
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{-42}{42}=-1$
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