21n-6(3n-2)=18

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Solution for 21n-6(3n-2)=18 equation: 



21n-6(3n-2)=18

We move all terms to the left:

21n-6(3n-2)-(18)=0

We multiply parentheses

21n-18n+12-18=0

We add all the numbers together, and all the variables

3n-6=0

We move all terms containing n to the left, all other terms to the right

3n=6

n=6/3

n=2

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