21x+10(x+1)=31(x+1)-21

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Solution for 21x+10(x+1)=31(x+1)-21 equation:


Simplifying
21x + 10(x + 1) = 31(x + 1) + -21

Reorder the terms:
21x + 10(1 + x) = 31(x + 1) + -21
21x + (1 * 10 + x * 10) = 31(x + 1) + -21
21x + (10 + 10x) = 31(x + 1) + -21

Reorder the terms:
10 + 21x + 10x = 31(x + 1) + -21

Combine like terms: 21x + 10x = 31x
10 + 31x = 31(x + 1) + -21

Reorder the terms:
10 + 31x = 31(1 + x) + -21
10 + 31x = (1 * 31 + x * 31) + -21
10 + 31x = (31 + 31x) + -21

Reorder the terms:
10 + 31x = 31 + -21 + 31x

Combine like terms: 31 + -21 = 10
10 + 31x = 10 + 31x

Add '-10' to each side of the equation.
10 + -10 + 31x = 10 + -10 + 31x

Combine like terms: 10 + -10 = 0
0 + 31x = 10 + -10 + 31x
31x = 10 + -10 + 31x

Combine like terms: 10 + -10 = 0
31x = 0 + 31x
31x = 31x

Add '-31x' to each side of the equation.
31x + -31x = 31x + -31x

Combine like terms: 31x + -31x = 0
0 = 31x + -31x

Combine like terms: 31x + -31x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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