21x+1=7(2x-1)+7x+8

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Solution for 21x+1=7(2x-1)+7x+8 equation: 



21x+1=7(2x-1)+7x+8

We move all terms to the left:

21x+1-(7(2x-1)+7x+8)=0



We calculate terms in parentheses: -(7(2x-1)+7x+8), so:

7(2x-1)+7x+8

We add all the numbers together, and all the variables

7x+7(2x-1)+8

We multiply parentheses

7x+14x-7+8

We add all the numbers together, and all the variables

21x+1

Back to the equation:

-(21x+1)



We get rid of parentheses

21x-21x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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