21x-19sin(x)=5

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Solution for 21x-19sin(x)=5 equation:


Simplifying
21x + -19sin(x) = 5

Multiply ins * x
21x + -19insx = 5

Reorder the terms:
-19insx + 21x = 5

Solving
-19insx + 21x = 5

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-21x' to each side of the equation.
-19insx + 21x + -21x = 5 + -21x

Combine like terms: 21x + -21x = 0
-19insx + 0 = 5 + -21x
-19insx = 5 + -21x

Divide each side by '-19nsx'.
i = -0.2631578947n-1s-1x-1 + 1.105263158n-1s-1

Simplifying
i = -0.2631578947n-1s-1x-1 + 1.105263158n-1s-1

Reorder the terms:
i = 1.105263158n-1s-1 + -0.2631578947n-1s-1x-1

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