21x-4(3x-4)=16+9x

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Solution for 21x-4(3x-4)=16+9x equation: 



21x-4(3x-4)=16+9x

We move all terms to the left:

21x-4(3x-4)-(16+9x)=0

We add all the numbers together, and all the variables

21x-4(3x-4)-(9x+16)=0

We multiply parentheses

21x-12x-(9x+16)+16=0

We get rid of parentheses

21x-12x-9x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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