21x-4-15x=2(3x-4)+4

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Solution for 21x-4-15x=2(3x-4)+4 equation: 



21x-4-15x=2(3x-4)+4

We move all terms to the left:

21x-4-15x-(2(3x-4)+4)=0

We add all the numbers together, and all the variables

6x-(2(3x-4)+4)-4=0



We calculate terms in parentheses: -(2(3x-4)+4), so:

2(3x-4)+4

We multiply parentheses

6x-8+4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

6x-6x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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