21x-5(x+4)=8(2x-3)+4

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Solution for 21x-5(x+4)=8(2x-3)+4 equation: 



21x-5(x+4)=8(2x-3)+4

We move all terms to the left:

21x-5(x+4)-(8(2x-3)+4)=0

We multiply parentheses

21x-5x-(8(2x-3)+4)-20=0



We calculate terms in parentheses: -(8(2x-3)+4), so:

8(2x-3)+4

We multiply parentheses

16x-24+4

We add all the numbers together, and all the variables

16x-20

Back to the equation:

-(16x-20)



We add all the numbers together, and all the variables

16x-(16x-20)-20=0

We get rid of parentheses

16x-16x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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