21x-5=2(7x-6)+7x+7

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Solution for 21x-5=2(7x-6)+7x+7 equation: 



21x-5=2(7x-6)+7x+7

We move all terms to the left:

21x-5-(2(7x-6)+7x+7)=0



We calculate terms in parentheses: -(2(7x-6)+7x+7), so:

2(7x-6)+7x+7

We add all the numbers together, and all the variables

7x+2(7x-6)+7

We multiply parentheses

7x+14x-12+7

We add all the numbers together, and all the variables

21x-5

Back to the equation:

-(21x-5)



We get rid of parentheses

21x-21x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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