21x-7+57x2=14x-3

Solution for 21x-7+57x2=14x-3 equation:

21x-7+57x^2=14x-3

We move all terms to the left:

21x-7+57x^2-(14x-3)=0

We get rid of parentheses

57x^2+21x-14x+3-7=0

We add all the numbers together, and all the variables

57x^2+7x-4=0

a = 57; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·57·(-4)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-31}{2*57}=\frac{-38}{114}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+31}{2*57}=\frac{24}{114}
=4/19
$