If it's not what You are looking for type in the equation solver your own equation and let us solve it.
21x^2-41x+10=0
a = 21; b = -41; c = +10;
Δ = b2-4ac
Δ = -412-4·21·10
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*21}=\frac{12}{42} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*21}=\frac{70}{42} =1+2/3 $
| 3(4x-1)^2=47 | | 16t^2-22t-108=0 | | -38=4(v-5)-6v | | 11+u=-5 | | -6(x+6)-4=-40 | | 14+9m=−13 | | 14+11=-5(3x-5) | | 0.5(x+100)=0.54x-250 | | 3(2x+9)=-50+41 | | |3x+4|=|6x-1| | | 7s+24+6s+28=65 | | 6+8x+2+18x=76 | | 5x-4(x-2)=7 | | 9(k-3)+3k=7k+43 | | 18x-35+5x2=0 | | 8(k+4)-2(k-1)=70-3k | | (x/5)+11=9x/3 | | x2=25/169 | | -6g=2-8g | | 1=-5+2v | | 0.4p-5=0.8p+3 | | 2(x+9)=45 | | 2w+2(23)=94 | | -6v=-1-7v | | 5-(3-x)=-6 | | |x-1|-5x=16 | | 4x+5-x-2=28 | | r-(-6)=8 | | 3x*10=310 | | 12-2x=9x+54 | | 2w+2(29)=100 | | -3r=-2r-7 |