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21x^2-5376=0
a = 21; b = 0; c = -5376;
Δ = b2-4ac
Δ = 02-4·21·(-5376)
Δ = 451584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{451584}=672$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-672}{2*21}=\frac{-672}{42} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+672}{2*21}=\frac{672}{42} =16 $
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