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21x^2-60x+36=0
a = 21; b = -60; c = +36;
Δ = b2-4ac
Δ = -602-4·21·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-24}{2*21}=\frac{36}{42} =6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+24}{2*21}=\frac{84}{42} =2 $
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