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21x^2-79x+36=0
a = 21; b = -79; c = +36;
Δ = b2-4ac
Δ = -792-4·21·36
Δ = 3217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{3217}}{2*21}=\frac{79-\sqrt{3217}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{3217}}{2*21}=\frac{79+\sqrt{3217}}{42} $
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