21x=2(5x-3)+11

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Solution for 21x=2(5x-3)+11 equation: 



21x=2(5x-3)+11

We move all terms to the left:

21x-(2(5x-3)+11)=0



We calculate terms in parentheses: -(2(5x-3)+11), so:

2(5x-3)+11

We multiply parentheses

10x-6+11

We add all the numbers together, and all the variables

10x+5

Back to the equation:

-(10x+5)



We get rid of parentheses

21x-10x-5=0

We add all the numbers together, and all the variables

11x-5=0

We move all terms containing x to the left, all other terms to the right

11x=5

x=5/11

x=5/11

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