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21x=3(5+2x)
We move all terms to the left:
21x-(3(5+2x))=0
We add all the numbers together, and all the variables
21x-(3(2x+5))=0
We calculate terms in parentheses: -(3(2x+5)), so:We get rid of parentheses
3(2x+5)
We multiply parentheses
6x+15
Back to the equation:
-(6x+15)
21x-6x-15=0
We add all the numbers together, and all the variables
15x-15=0
We move all terms containing x to the left, all other terms to the right
15x=15
x=15/15
x=1
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