21x=4(4x+70)

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Solution for 21x=4(4x+70) equation: 



21x=4(4x+70)

We move all terms to the left:

21x-(4(4x+70))=0



We calculate terms in parentheses: -(4(4x+70)), so:

4(4x+70)

We multiply parentheses

16x+280

Back to the equation:

-(16x+280)



We get rid of parentheses

21x-16x-280=0

We add all the numbers together, and all the variables

5x-280=0

We move all terms containing x to the left, all other terms to the right

5x=280

x=280/5

x=56

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