21x=4(5x+7)

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Solution for 21x=4(5x+7) equation: 



21x=4(5x+7)

We move all terms to the left:

21x-(4(5x+7))=0



We calculate terms in parentheses: -(4(5x+7)), so:

4(5x+7)

We multiply parentheses

20x+28

Back to the equation:

-(20x+28)



We get rid of parentheses

21x-20x-28=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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