21y-18=3(7y-6)

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Solution for 21y-18=3(7y-6) equation: 



21y-18=3(7y-6)

We move all terms to the left:

21y-18-(3(7y-6))=0



We calculate terms in parentheses: -(3(7y-6)), so:

3(7y-6)

We multiply parentheses

21y-18

Back to the equation:

-(21y-18)



We get rid of parentheses

21y-21y+18-18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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