22(20-x)+36(20+x)=3

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Solution for 22(20-x)+36(20+x)=3 equation: 



22(20-x)+36(20+x)=3

We move all terms to the left:

22(20-x)+36(20+x)-(3)=0

We add all the numbers together, and all the variables

22(-1x+20)+36(x+20)-3=0

We multiply parentheses

-22x+36x+440+720-3=0

We add all the numbers together, and all the variables

14x+1157=0

We move all terms containing x to the left, all other terms to the right

14x=-1157

x=-1157/14

x=-82+9/14

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