22(3-x)+12=96

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Solution for 22(3-x)+12=96 equation: 



22(3-x)+12=96

We move all terms to the left:

22(3-x)+12-(96)=0

We add all the numbers together, and all the variables

22(-1x+3)+12-96=0

We add all the numbers together, and all the variables

22(-1x+3)-84=0

We multiply parentheses

-22x+66-84=0

We add all the numbers together, and all the variables

-22x-18=0

We move all terms containing x to the left, all other terms to the right

-22x=18

x=18/-22

x=-9/11

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