22(3-x)+12=96

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Solution for 22(3-x)+12=96 equation:



22(3-x)+12=96
We move all terms to the left:
22(3-x)+12-(96)=0
We add all the numbers together, and all the variables
22(-1x+3)+12-96=0
We add all the numbers together, and all the variables
22(-1x+3)-84=0
We multiply parentheses
-22x+66-84=0
We add all the numbers together, and all the variables
-22x-18=0
We move all terms containing x to the left, all other terms to the right
-22x=18
x=18/-22
x=-9/11

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