22(3-x)+12x=96

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Solution for 22(3-x)+12x=96 equation: 



22(3-x)+12x=96

We move all terms to the left:

22(3-x)+12x-(96)=0

We add all the numbers together, and all the variables

22(-1x+3)+12x-96=0

We add all the numbers together, and all the variables

12x+22(-1x+3)-96=0

We multiply parentheses

12x-22x+66-96=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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