22(3b-4)=5(b+6)

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Solution for 22(3b-4)=5(b+6) equation: 



22(3b-4)=5(b+6)

We move all terms to the left:

22(3b-4)-(5(b+6))=0

We multiply parentheses

66b-(5(b+6))-88=0



We calculate terms in parentheses: -(5(b+6)), so:

5(b+6)

We multiply parentheses

5b+30

Back to the equation:

-(5b+30)



We get rid of parentheses

66b-5b-30-88=0

We add all the numbers together, and all the variables

61b-118=0

We move all terms containing b to the left, all other terms to the right

61b=118

b=118/61

b=1+57/61

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