22(a-20)=128

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Solution for 22(a-20)=128 equation: 



22(a-20)=128

We move all terms to the left:

22(a-20)-(128)=0

We multiply parentheses

22a-440-128=0

We add all the numbers together, and all the variables

22a-568=0

We move all terms containing a to the left, all other terms to the right

22a=568

a=568/22

a=25+9/11

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