22(a-20)=128

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Solution for 22(a-20)=128 equation:



22(a-20)=128
We move all terms to the left:
22(a-20)-(128)=0
We multiply parentheses
22a-440-128=0
We add all the numbers together, and all the variables
22a-568=0
We move all terms containing a to the left, all other terms to the right
22a=568
a=568/22
a=25+9/11

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