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22(x-5)+2x=4(x+2)-18
We move all terms to the left:
22(x-5)+2x-(4(x+2)-18)=0
We add all the numbers together, and all the variables
2x+22(x-5)-(4(x+2)-18)=0
We multiply parentheses
2x+22x-(4(x+2)-18)-110=0
We calculate terms in parentheses: -(4(x+2)-18), so:We add all the numbers together, and all the variables
4(x+2)-18
We multiply parentheses
4x+8-18
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
24x-(4x-10)-110=0
We get rid of parentheses
24x-4x+10-110=0
We add all the numbers together, and all the variables
20x-100=0
We move all terms containing x to the left, all other terms to the right
20x=100
x=100/20
x=5
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