22(x-5)-3(3-x)=0.5(x-2)

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Solution for 22(x-5)-3(3-x)=0.5(x-2) equation: 



22(x-5)-3(3-x)=0.5(x-2)

We move all terms to the left:

22(x-5)-3(3-x)-(0.5(x-2))=0

We add all the numbers together, and all the variables

22(x-5)-3(-1x+3)-(0.5(x-2))=0

We multiply parentheses

22x+3x-(0.5(x-2))-110-9=0



We calculate terms in parentheses: -(0.5(x-2)), so:

0.5(x-2)

We multiply parentheses

0.5x-1

Back to the equation:

-(0.5x-1)



We add all the numbers together, and all the variables

25x-(0.5x-1)-119=0

We get rid of parentheses

25x-0.5x+1-119=0

We add all the numbers together, and all the variables

24.5x-118=0

We move all terms containing x to the left, all other terms to the right

24.5x=118

x=118/24.5

x=4+5/6.125

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