22(y+1)+7=3(y-2)+2y

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Solution for 22(y+1)+7=3(y-2)+2y equation: 



22(y+1)+7=3(y-2)+2y

We move all terms to the left:

22(y+1)+7-(3(y-2)+2y)=0

We multiply parentheses

22y-(3(y-2)+2y)+22+7=0



We calculate terms in parentheses: -(3(y-2)+2y), so:

3(y-2)+2y

We add all the numbers together, and all the variables

2y+3(y-2)

We multiply parentheses

2y+3y-6

We add all the numbers together, and all the variables

5y-6

Back to the equation:

-(5y-6)



We add all the numbers together, and all the variables

22y-(5y-6)+29=0

We get rid of parentheses

22y-5y+6+29=0

We add all the numbers together, and all the variables

17y+35=0

We move all terms containing y to the left, all other terms to the right

17y=-35

y=-35/17

y=-2+1/17

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