22+2(2x+1)=4(3x-2)

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Solution for 22+2(2x+1)=4(3x-2) equation: 



22+2(2x+1)=4(3x-2)

We move all terms to the left:

22+2(2x+1)-(4(3x-2))=0

We multiply parentheses

4x-(4(3x-2))+2+22=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We add all the numbers together, and all the variables

4x-(12x-8)+24=0

We get rid of parentheses

4x-12x+8+24=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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