22+2v=-4(4+8v)-4v

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Solution for 22+2v=-4(4+8v)-4v equation: 



22+2v=-4(4+8v)-4v

We move all terms to the left:

22+2v-(-4(4+8v)-4v)=0

We add all the numbers together, and all the variables

2v-(-4(8v+4)-4v)+22=0



We calculate terms in parentheses: -(-4(8v+4)-4v), so:

-4(8v+4)-4v

We add all the numbers together, and all the variables

-4v-4(8v+4)

We multiply parentheses

-4v-32v-16

We add all the numbers together, and all the variables

-36v-16

Back to the equation:

-(-36v-16)



We get rid of parentheses

2v+36v+16+22=0

We add all the numbers together, and all the variables

38v+38=0

We move all terms containing v to the left, all other terms to the right

38v=-38

v=-38/38

v=-1

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