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22+3x=3(-x+3)-11
We move all terms to the left:
22+3x-(3(-x+3)-11)=0
We add all the numbers together, and all the variables
3x-(3(-1x+3)-11)+22=0
We calculate terms in parentheses: -(3(-1x+3)-11), so:We get rid of parentheses
3(-1x+3)-11
We multiply parentheses
-3x+9-11
We add all the numbers together, and all the variables
-3x-2
Back to the equation:
-(-3x-2)
3x+3x+2+22=0
We add all the numbers together, and all the variables
6x+24=0
We move all terms containing x to the left, all other terms to the right
6x=-24
x=-24/6
x=-4
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