22+4n=6(n+2)

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Solution for 22+4n=6(n+2) equation: 



22+4n=6(n+2)

We move all terms to the left:

22+4n-(6(n+2))=0



We calculate terms in parentheses: -(6(n+2)), so:

6(n+2)

We multiply parentheses

6n+12

Back to the equation:

-(6n+12)



We get rid of parentheses

4n-6n-12+22=0

We add all the numbers together, and all the variables

-2n+10=0

We move all terms containing n to the left, all other terms to the right

-2n=-10

n=-10/-2

n=+5

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