22+4v=2(8-v)

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Solution for 22+4v=2(8-v) equation: 



22+4v=2(8-v)

We move all terms to the left:

22+4v-(2(8-v))=0

We add all the numbers together, and all the variables

4v-(2(-1v+8))+22=0



We calculate terms in parentheses: -(2(-1v+8)), so:

2(-1v+8)

We multiply parentheses

-2v+16

Back to the equation:

-(-2v+16)



We get rid of parentheses

4v+2v-16+22=0

We add all the numbers together, and all the variables

6v+6=0

We move all terms containing v to the left, all other terms to the right

6v=-6

v=-6/6

v=-1

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