22+5(x+3)=-3+2(x-4)

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Solution for 22+5(x+3)=-3+2(x-4) equation: 



22+5(x+3)=-3+2(x-4)

We move all terms to the left:

22+5(x+3)-(-3+2(x-4))=0

We multiply parentheses

5x-(-3+2(x-4))+15+22=0



We calculate terms in parentheses: -(-3+2(x-4)), so:

-3+2(x-4)

determiningTheFunctionDomain
2(x-4)-3

We multiply parentheses

2x-8-3

We add all the numbers together, and all the variables

2x-11

Back to the equation:

-(2x-11)



We add all the numbers together, and all the variables

5x-(2x-11)+37=0

We get rid of parentheses

5x-2x+11+37=0

We add all the numbers together, and all the variables

3x+48=0

We move all terms containing x to the left, all other terms to the right

3x=-48

x=-48/3

x=-16

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