22+9c-c2=0

Solution for 22+9c-c2=0 equation:

22+9c-c2=0

We add all the numbers together, and all the variables

-1c^2+9c+22=0

a = -1; b = 9; c = +22;
Δ = b2-4ac
Δ = 92-4·(-1)·22
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-13}{2*-1}=\frac{-22}{-2}
=+11
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+13}{2*-1}=\frac{4}{-2}
=-2
$