22+k=3(k+2)

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Solution for 22+k=3(k+2) equation: 



22+k=3(k+2)

We move all terms to the left:

22+k-(3(k+2))=0



We calculate terms in parentheses: -(3(k+2)), so:

3(k+2)

We multiply parentheses

3k+6

Back to the equation:

-(3k+6)



We get rid of parentheses

k-3k-6+22=0

We add all the numbers together, and all the variables

-2k+16=0

We move all terms containing k to the left, all other terms to the right

-2k=-16

k=-16/-2

k=+8

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