22+y/x=z/t

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Solution for 22+y/x=z/t equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y/x+22 = z/t // - z/t

y/x-(z/t)+22 = 0

x^-1*y = -(22-(t^-1*z)) // : y

x^-1 = (t^-1*z-22)/y

-1 < 0

1/(x^1) = (t^-1*z-22)/y // * x^1

1 = x^1*((t^-1*z-22)/y) // : (t^-1*z-22)/y

1/((t^-1*z-22)/y) = x^1

x = 1/((t^-1*z-22)/y)

x = 1/((t^-1*z-22)/y)

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