22-(3c+4)=2(c+3)+c

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Solution for 22-(3c+4)=2(c+3)+c equation:


Simplifying
22 + -1(3c + 4) = 2(c + 3) + c

Reorder the terms:
22 + -1(4 + 3c) = 2(c + 3) + c
22 + (4 * -1 + 3c * -1) = 2(c + 3) + c
22 + (-4 + -3c) = 2(c + 3) + c

Combine like terms: 22 + -4 = 18
18 + -3c = 2(c + 3) + c

Reorder the terms:
18 + -3c = 2(3 + c) + c
18 + -3c = (3 * 2 + c * 2) + c
18 + -3c = (6 + 2c) + c

Combine like terms: 2c + c = 3c
18 + -3c = 6 + 3c

Solving
18 + -3c = 6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
18 + -3c + -3c = 6 + 3c + -3c

Combine like terms: -3c + -3c = -6c
18 + -6c = 6 + 3c + -3c

Combine like terms: 3c + -3c = 0
18 + -6c = 6 + 0
18 + -6c = 6

Add '-18' to each side of the equation.
18 + -18 + -6c = 6 + -18

Combine like terms: 18 + -18 = 0
0 + -6c = 6 + -18
-6c = 6 + -18

Combine like terms: 6 + -18 = -12
-6c = -12

Divide each side by '-6'.
c = 2

Simplifying
c = 2

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