22-(n-3)=5(n+4)

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Solution for 22-(n-3)=5(n+4) equation:



22-(n-3)=5(n+4)
We move all terms to the left:
22-(n-3)-(5(n+4))=0
We get rid of parentheses
-n-(5(n+4))+3+22=0
We calculate terms in parentheses: -(5(n+4)), so:
5(n+4)
We multiply parentheses
5n+20
Back to the equation:
-(5n+20)
We add all the numbers together, and all the variables
-1n-(5n+20)+25=0
We get rid of parentheses
-1n-5n-20+25=0
We add all the numbers together, and all the variables
-6n+5=0
We move all terms containing n to the left, all other terms to the right
-6n=-5
n=-5/-6
n=5/6

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